If the lines `x-2y + 3 = 0 , 3x + ky + 7=0` cut the coordinate axes in concyclic points, then k=

If the lines x-2y+3=0, 3x+ky+7=0 cut the coordinate axes in concylic points, then k=

If the lines x-2y+3=0, 3x+ky+7=0 cut the coordinate axes in concylic points, then k=

The algebraic sum of distances of the line ax + by + 2 = 0 from (1,2), (2,1) and (3,5) is zero and the lines bx - ay + 4 = 0 and 3x + 4y + 5=0 cut the coordinate axes at concyclic points. Then (a) a+b=-2/7 (b) area of triangle formed by the line ax+by+2=0 with coordinate axes is 14/5 (c) line ax+by+3=0 always passes through the point (-1,1) (d) max {a,b}=5/7

The algebraic sum of distances of the line ax + by + 2 = 0 from (1,2), (2,1) and (3,5) is zero and the lines bx - ay + 4 = 0 and 3x + 4y + 5=0 cut the coordinate axes at concyclic points. Then (a) a+b=-2/7 (b) area of triangle formed by the line ax+by+2=0 with coordinate axes is 14/5 (c) line ax+by+3=0 always passes through the point (-1,1) (d) max {a,b}=5/7

If the lines 2x-3y+7=0, 3x+ky+5=0 cut the coordinate axes in concyclic points then k=

If the lines 2x-3y+7=0, 3x+ky+5=0 cut the coordinate axes in concyclie points then k=

The lines ax + 3y + 19 = 0 and 9x + 6y-17 = 0 cut the coordinate axes in concyclic points then a =

If the lines 2x+3y-1=0 and kx-y+4=0 intersect the coordinate axes in concyclic points then k-1=

If the line 2x+3y+1=0, 3x+2y-1=0 intersect the coordinate axes in fourc concyclic points then the equation of the circle passing through these four points is