" (v) "log_(4)(2log_(3)(1+log_(2)(1+3log_(3)x)))=1/2

If x=3, then log_(4)(2log_(3)(1+log_(2)(1+3log_(3)x))) is equal to

The number of values of x if log_4(2log_3(1+log_2(1+3log_3x)))=1/2

(log_(5)4)(log_(4)3)(log_(3)2)(log_(2)1) =

log_(2)log_(3)log_(4)(x-1)>0

log_(2)(x+1)-log_(2)(3x-1)=2

log_(2)(3-x)+log_(2)(1-x)=3

(log_(2)(log_((1)/(2))(log_(2)a)))^(2)+(log_(3)(log_((1)/(3))(log_(3)b)))^(2)=0,then(alpha^(2)+b^(3)) is greater then

(log_(4)x-2)*log_(4)x=(3)/(2)(log_(4)x-1)

Solve :log_(3)(1+log_(3)(2^(x)-7))=1

" 4) "log_(8)1+log_(8)2+log_(8)8=log_(8)(1+2+3)