A line is such that its segment between the lines `5x-y + 4 = 0`and `3x + 4y -4 = 0` is bisected at the point (1, 5). Obtain its equation.

Explanation

To find the equation of the line that is bisected at the point (1, 5) between the lines \(5x - y + 4 = 0\) and \(3x + 4y - 4 = 0\), we will follow these steps:

### Step 1: Identify the equations of the given lines
The equations of the lines are:
1. Line 1: \(5x - y + 4 = 0\)
2. Line 2: \(3x + 4y - 4 = 0\)

### Step 2: Find the slope and intercepts of the lines
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