From the origin, chords are drawn to the circle `(x-1)^2 + y^2 = 1`. The equation of the locus of the mid-points of these chords is circle with radius

From the origin chords are drawn to the circle (x-1)^(2)+y^(2)=1 then equation of locus of mid ponts of these chords is

From the origin chords are drawn to the circle (x-1)^(2)+y^(2)=1 . Show that the equation of the locus of the mid points of these chords is x^(2)+y^(2)=x=0

Determine the locus of the mid-points of equals chords of a circle .

The locus of the mid points of all equal chords in a circle is :

From the origin chords are drawn to the circle x^(2)+y^(2)-2y=0 . The locus of the middle points of these chords is

If from the origin a chord is drawn to the circle x^(2)+y^(2)-2x=0 , then the locus of the mid point of the chord has equation

From (3,4) chords are drawn to the circle x^(2)+y^(2)-4x=0. The locus of the mid points of the chords is :

Tangents are drawn to a unit circle with centre at the origin from each point on the line 2x + y = 4 . Then the equation to the locus of the middle point of the chord of contact is

From origin chords are drawn to the cirlce x^(2)+y^(2)-2px=0 then locus of midpoints of all such chords is