In an AP,`S_p=q`,`S_q=p` . Then `S_[p+q]` is equal to :

in an AP , S_p=q , S_q=p and S_r denotes the sum of the first r terms. Then S_(p+q)=

in an AP,S_(p)=q,S_(q)=p and S_(r) denotes the sum of the first r terms.Then S_(p+q)=

If S^(*)(p,q) is the dual of the compound statement S(p,q) then S^(*)(sim p,sim q) is equivalent to-

Sum of products P,Q,R,S (i.e. P+Q+R+S) is equal to:

Match the following column s: Column-I " " Column-II Negation of (~ p->q) is " " p. [~(p v q)]^^[p v(~ p)] Negation of (pharrq) " " q. (p^^~ q)vv(~ p^^q) Negation of (pvvq)i s " " r. ~ p^^~ q pharrq is equivalent to " " s. ~ p^^~ q