Young's modulus of a metal is `15xx10^(11) Pa`. If its Poisson's ratio is `0.4`. The bulk modulus of the metal in `Pa` is

If bulk modulus of the metal is 2xx10^(12)Pa and Poisson's ratio is 0.4 then young's modulus of the metal is

The Young's modulus of a material is 10^(11)N//m^(2) and its Poisson's ratio is 0.2 . The modulus of rigidity of the material is

Bulk modulus of a material is 2.5xx10^(11)"dyne"//cm^(2) and Poisson's ratio is 0.4. Then young's modulus for such material ios

Young modulus of a material =18.5 times 10^10 N.m^-2 and its poisson's ratio is 0.238. Determine the bulk modulus and modulus of rigidity for the material.

Young's modulus of a metal is 21xx10^(10)N//m^(2) . Express it in "dyne/cm"^(2) .

The bulk modulus of a metal is 8 xx 10^(9) Nm^(-2) and its density is 11 g cm^(-2) . The density of this metal under a pressure of 20000 N cm^(-2) will be (in g cm^(-3) )

The Young's modulus of steel is 2xx10^(11)N//m^(2) . If the interatomic spacing of the metal is 2.5 Å. Then the interatomic force constant is,

The bulk of modulus of a metal is 10^(10)(N)/(m^2) and Poisson's ratio 0.20 . If average distance between the molecules is 3Å the the interatomic force constant is

Given Young's modulus of elasticity for nickel as 207xx10^(9)Nm^(-2) and Poisson's ratio 0.36 calculate its rigidity modulus and bulk modilus of elasticity.