The e.m.f. of a cell is E volts and internal resistance is r ohm. The resistance in exteral circuit is also r ohm. The p.d across the cell will be

The emf of a cell is E volt and internal resistance is r ohm. It resistance in the external circuit is r ohm, the p.d. across the cell will be

In the adjoining circuit, the e.m.f. of the cell is 2 volt and the internal resistance is negligible. The resistance of the voltmeter is 80 ohm . The reading of the voltmeter will be

In the adjoining circuit, the e.m.f. of the cell is 2 volt and the internal resistance is negligible. The resistance of the voltmeter is 80 ohm . The reading of the voltmeter will be

The e.m.f. of a cell is 2.0 volt and the internal resistance is 0.1ohm. It is connected with a resistance of 3.9ohm. Then potential difference across the cell is :–

A current of 2.0 ampere passes through a cell of e.m.f. 1.5 volts having internal resistance of 0.15 ohm. The potential difference measured, in volts, across both the ends of the cell will be

A current of 2.0 ampere passes through a cell of e.m.f. 1.5 volts having internal resistance of 0.15 ohm. The potential difference measured, in volts, across both the ends of the cell will be

The diagram in Fig. shows a cell of e.m.f. epsi = 2 volt and internal resistance r = 1 ohm connected to an external resistance R = 4 ohm. The ammeter A measures the current in the circuit and the voltmeter V measures the terminal voltage across the cell. What will be the readings of the ammeter and voltmeter when the key K is open

The diagram in Fig. shows a cell of e.m.f. epsi = 2 volt and internal resistance r = 1 ohm connected to an external resistance R = 4 ohm. The ammeter A measures the current in the circuit and the voltmeter V measures the terminal voltage across the cell. What will be the readings of the ammeter and voltmeter when the key K is closed.