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If A={:[(0,0,0),(0,0,0),(1,0,0)]:}, then...

If `A={:[(0,0,0),(0,0,0),(1,0,0)]:}`, then

A

`A^(2)=0`

B

`A^(2)=A`

C

`A^(3)=A`

D

`A^(2)=2A`

Text Solution

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The correct Answer is:
To solve the problem, we need to find \( A^2 \) where \( A \) is given as: \[ A = \begin{pmatrix} 0 & 0 & 0 \\ 0 & 0 & 0 \\ 1 & 0 & 0 \end{pmatrix} \] ### Step 1: Write down the matrix A We have the matrix \( A \): \[ A = \begin{pmatrix} 0 & 0 & 0 \\ 0 & 0 & 0 \\ 1 & 0 & 0 \end{pmatrix} \] ### Step 2: Calculate \( A^2 \) (which is \( A \times A \)) To find \( A^2 \), we perform the matrix multiplication \( A \times A \). \[ A^2 = A \times A = \begin{pmatrix} 0 & 0 & 0 \\ 0 & 0 & 0 \\ 1 & 0 & 0 \end{pmatrix} \times \begin{pmatrix} 0 & 0 & 0 \\ 0 & 0 & 0 \\ 1 & 0 & 0 \end{pmatrix} \] ### Step 3: Perform the multiplication We will calculate each element of the resulting matrix \( A^2 \). - **Element (1,1)**: \[ 0 \times 0 + 0 \times 0 + 0 \times 1 = 0 \] - **Element (1,2)**: \[ 0 \times 0 + 0 \times 0 + 0 \times 0 = 0 \] - **Element (1,3)**: \[ 0 \times 0 + 0 \times 0 + 0 \times 0 = 0 \] - **Element (2,1)**: \[ 0 \times 0 + 0 \times 0 + 0 \times 1 = 0 \] - **Element (2,2)**: \[ 0 \times 0 + 0 \times 0 + 0 \times 0 = 0 \] - **Element (2,3)**: \[ 0 \times 0 + 0 \times 0 + 0 \times 0 = 0 \] - **Element (3,1)**: \[ 1 \times 0 + 0 \times 0 + 0 \times 1 = 0 \] - **Element (3,2)**: \[ 1 \times 0 + 0 \times 0 + 0 \times 0 = 0 \] - **Element (3,3)**: \[ 1 \times 0 + 0 \times 0 + 0 \times 0 = 0 \] ### Step 4: Write down the resulting matrix After performing the multiplication, we find: \[ A^2 = \begin{pmatrix} 0 & 0 & 0 \\ 0 & 0 & 0 \\ 0 & 0 & 0 \end{pmatrix} \] ### Conclusion Thus, we conclude that: \[ A^2 = 0 \]
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