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Find the equation of the straight line which is at a distance 3 from the origin and perpendicular from the origin to the line makes an angle of `30^0` with the positive direction of the x-axis.

Text Solution

Verified by Experts

By the normal from,
`x cos omega+y sin omega=p`
Here, ` p=3and omega=30^(@)`
The required equation is
`thereforex=cos30^(@)+ysin30^(@)=3`
`(sqrt3x)/(2)+y/2=3`
sqrt3x+y=6`
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