Find the equation of image line and reflected line of 2x+3y-5=0 through the line mirror y=x

Explanation

`y=x" "...(i)`
`2x+3y-5=0" "...(ii)`
By (i) and (iii) `x=y=1`
`impliesB-=(1,1)`
Let -=`A=((5)/(2),0)impliesA'=(0,(5)/(2))`
(image through `y=x)`

The equation of BA' is `y-1=((5)/(2)-1)/(0-1)(x-1)`
`impliesy-1=-3/2(x-1)`
`2y-2=-3x+3`
`2y+3x=5`
`2y+3x-5=0`
This is also the equation of reflected line.