Transform the equation of the line `sqrt(3)x+y-8=0` to (i) slope intercept form and find its slope and y-intercept (ii) intercept form and find intercepts in the coordinates axes (iii) normal form and find the inclination of the perpendicular segment from the origin on the line with the axis and its length.

Answer

(a) Slope `-sqrt3,` y-interxcept =8
(b) x-intercept `=(8)/(sqrt3),` y-intercept =8
(c ) `p=4omega=(pi)/(6)`