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The slope of the line passing through th...

The slope of the line passing through the points `(a^(2),b)and (b^(2),a)` is

A

`(1)/(a+b)`

B

`a+b`

C

`(-1)/(a+b)`

D

`-(a+b)`

Text Solution

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The correct Answer is:
To find the slope of the line passing through the points \((a^2, b)\) and \((b^2, a)\), we can use the slope formula. The slope \(m\) of a line passing through two points \((x_1, y_1)\) and \((x_2, y_2)\) is given by: \[ m = \frac{y_2 - y_1}{x_2 - x_1} \] ### Step-by-Step Solution: 1. **Identify the Points**: The points given are \((x_1, y_1) = (a^2, b)\) and \((x_2, y_2) = (b^2, a)\). 2. **Substitute the Points into the Slope Formula**: Substitute \(x_1, y_1, x_2, y_2\) into the slope formula: \[ m = \frac{a - b}{b^2 - a^2} \] 3. **Factor the Denominator**: The denominator \(b^2 - a^2\) can be factored using the difference of squares: \[ b^2 - a^2 = (b - a)(b + a) \] 4. **Rewrite the Slope**: Now substitute the factored form back into the slope equation: \[ m = \frac{a - b}{(b - a)(b + a)} \] 5. **Simplify the Expression**: Notice that \(a - b = -(b - a)\), so we can rewrite the slope as: \[ m = \frac{-(b - a)}{(b - a)(b + a)} \] 6. **Cancel Common Terms**: The \((b - a)\) terms in the numerator and denominator cancel out (as long as \(b \neq a\)): \[ m = \frac{-1}{b + a} \] ### Final Result: The slope of the line passing through the points \((a^2, b)\) and \((b^2, a)\) is: \[ m = -\frac{1}{b + a} \]
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