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The equation of line passing through the...

The equation of line passing through the point `(-4,-5)` and perpendicular to the line joining the points `(1,2)and (5,6)` is

A

`x+y-9=0`

B

`x+y+9=0`

C

`x=y+9`

D

`y=x+9`

Text Solution

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The correct Answer is:
B
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Knowledge Check

  • Find the equation of the line passing through the point (-4,-5) and perpendicular to the line joining the points (1,2) and (5,6)

    A
    a. x+y+17=0
    B
    b. 3x+2y+11=0
    C
    c. x+y+8=0
    D
    d. x-y+20=0

  • The equation of the plane passing through the point (-10,5,4) and perpendicular to the line joining the points (4,-1,2) and (-3,2,3) is

    A
    7x-3y-z+89=0
    B
    7x-3y-z-89=0
    C
    7x+3y-z+89=0
    D
    7x-3y+z-89=0

  • The equation of the plane passing through the point (-1, 2, 1) and perpendicular to the line joining the points (-3, 1, 2) and (2, 3, 4) is · · · · · ·

    A
    `rdot(5hati+2hatj+2hatk)=1`
    B
    `rdot(5hati+2hatj+2hatk)=-1`
    C
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    D
    `rdot(5hati-2hatj-2hatk)=1`

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    Equation of line passing through the point (2,-3) and perpendicular to the straight line joining the points (5,7) and (-6,3).

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