Find the equation of the circle passes through the points `(2, 1)` and `(-2, 3)` and has centre on the line `x + y + 4 = 0`

Explanation

To find the equation of the circle that passes through the points (2, 1) and (-2, 3) and has its center on the line \( x + y + 4 = 0 \), we can follow these steps:

### Step 1: Write the general equation of the circle
The general equation of a circle with center \((h, k)\) and radius \(r\) is given by:
\[ (x - h)^2 + (y - k)^2 = r^2 \]

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