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Find the equation of ellipse whose vetic...

Find the equation of ellipse whose vetices are `(5, 0)` and foci are `( pm 4, 0)`

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Since, the vertices are on the x-axis the equation will be the form `(x^(2))/(a^(2))+(y^(2))/(b^(2))=1`, where 'a' is the semi-major axis.
Given that a = 5 and c = 4
`therefore` From the relation `c^(2) = a^(2)-b^(2)`, we get : `16 = 25 -b^(2)`
`rArr b^(2) = 9`
Hence, the equation of the ellipse is `(x^(2))/(25) + (y^(2))/(9) =1`
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