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If (x^(2))/(36) - (y^(2))/(64) =1 repres...

If `(x^(2))/(36) - (y^(2))/(64) =1` represents a hyperbola, then find the co-ordinates of the foci and the vertices, the eccentricity and the length of the latus rectum.

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To solve the problem, we start with the given hyperbola equation: \[ \frac{x^2}{36} - \frac{y^2}{64} = 1 \] ### Step 1: Identify values of \(a\) and \(b\) ...
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