The equation of the locus of the mid-poi...

The equation of the locus of the mid-points of chords of the circle `4x^(2) + 4y^(2) -12x + 4y + 1 = 0` that substend an angle `(2pi)/(3)` at its centre, is

`16x^(2) + 16y^(2) -48x + 16y + 31 = 0`

`16x^(2) + 16y^(2) + 48x + 48y + 31 = 0`

`16x^(2) - 16y^(2) + 48x + 48y + 31 = 0`

`16x^(2) - 16y^(2) - 48x + 16y - 31 = 0`

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The equation of the locus of the mid-points of chords of the circle 4x^(2)+4y^(2)-12x+4y+1=0 that subtends an angle of at its centre is (2 pi)/(3) at its centre is x^(2)+y^(2)-kx+y+(31)/(16)=0 then k is

The equation of the locus of the mid-points of chords of the circle 4x^(2)+4y^(2)-12x+4y+1=0 that subtends an angle of at its centre is 2(pi)/(3) at its centre is x^(2)+y^(2)-kx+y+(31)/(16)=0 then k is

The locus of the mid points of the chords of the circle x^(2)+y^(2)+4x-6y-12=0 which subtends an angle of (pi)/(3) radians at its centre is

The locus of the mid-points of the chords of the circles x^(2)+y^(2)-2x-4y-11=0 which subtends an angle of 60 at centre is

Let C be the circle with centre (0,0) and radius 3 units.The equation of the locus of the mid points of the chords of the circle C that subtend an angle of (2 pi)/(3) at its center is (A) x^(2)+y^(2)=(3)/(2)(B)x^(2)+y^(2)=1(C)x^(2)+y^(2)=(27)/(4)(D)x^(2)+y^(2)=(9)/(4)

Let C be the circle with centre (0,0) and radius 3 units.The equation of the locus of the mid points of the chords of the circle C that subtend an angle of (2 pi)/(3) at its center is (a) x^(2)+y^(2)=(3)/(2)(b)x^(2)+y^(2)=1(c)x^(2)+y^(2)=(27)/(4)(d)x^(2)+y^(2)=(9)/(4)

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