If the circle x^(2) + y^(2) -4x - 8y + 1...

If the circle `x^(2) + y^(2) -4x - 8y + 16 =0` rolls up the tangent to it at `(2 + sqrt(3), 3)` by 2 units (assumes x-axis as horizontal), then the centre of the circle in the new position is

(3, 4)

`(3sqrt(3), 4 + sqrt(3))`

`(3, 4 + sqrt(3))`

`(3 + sqrt(3), 4 + sqrt(3))`

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