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A circle of constant radius r passes through the origin O, and cuts the axes at A and B. The locus of the foots the perpendicular from O to AB is `(x^(2) + y^(2)) =4r^(2)x^(2)y^(2)`, Then the value of k is

A

2

B

1

C

3

D

4

Text Solution

Verified by Experts

The correct Answer is:
C
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