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The vertex of the parabola y^2 = 8x is a...

The vertex of the parabola `y^2 = 8x` is at the centre of a circle and the parabola cuts the circle at the ends of itslatus rectum. Then the equation of the circle is

A

`x^(2) + y^(2) = 4`

B

`x^(2) + y^(2) = 20`

C

`x^(2) + y^(2) = 80`

D

`x^(2) + y^(2) = 1`

Text Solution

Verified by Experts

The correct Answer is:
B
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AAKASH INSTITUTE-CONIC SECTIONS-SECTION-B
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  18. The centre of the ellipse 4x^(2) + 9y^(2) + 16 - 18y - 11 = 0 is

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