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If tangents are drawn to the ellipse `2x^(2) + 3y^(2) =6`, then the locus of the mid-point of the intercept made by the tangents between the co-ordinate axes is

A

`(1)/(4x^(2)) + (1)/(2y^(2)) =1`

B

`(3)/(4x^(2)) + (1)/(2y^(2)) =1`

C

`(1)/(x^(2)) + (1)/(y^(2)) =1`

D

`(1)/(x^(2)) + (3)/(4y^(2)) =1`

Text Solution

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The correct Answer is:
B
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