If equation of hyperbola is 4(2y -x -3)^...

If equation of hyperbola is `4(2y -x -3)^(2) -9(2x + y - 1)^(2) = 80`, then

Eccentricity is `(sqrt(13))/(3)`

Centre of hyperbola is `(-(7)/(5),-(7)/(5))`

Transverse axis is `2x + y -1 = 0`

Conjugate axis is `x -2y + 3 = 0`

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