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Prove (A cap B)'=(A' cup B')...

Prove `(A cap B)'=(A' cup B')`

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For all `x in (A cap B)`
`Leftrightarrow x in (A cap B)`
`Leftrightarrow x notin (A cap B)`
`Leftrightarrow x notin A or x notin B`
`Leftrightarrow x in A' or x in B`
`Leftrightarrow x in A' cup B`
Hence, `(A cap B)'=A' cup B`
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