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If A={phi,{phi}},"then P(A) is"...

If `A={phi,{phi}},"then P(A) is"`

A

`{phi,{phi}}`

B

`{phi,{phi}},{{phi}}}`

C

`{phi,{phi},{{phi}},{phi,{phi}}}`

D

`{phi}`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the power set of the set \( A = \{ \phi, \{ \phi \} \} \). ### Step-by-Step Solution: 1. **Identify the Set \( A \)**: The set \( A \) consists of two elements: the empty set \( \phi \) and the set containing the empty set \( \{ \phi \} \). Thus, we can write: \[ A = \{ \phi, \{ \phi \} \} \] 2. **Determine the Number of Elements in Set \( A \)**: The set \( A \) has 2 elements. Therefore, we can denote the number of elements in \( A \) as: \[ n(A) = 2 \] 3. **Calculate the Number of Elements in the Power Set \( P(A) \)**: The power set \( P(A) \) of a set with \( n \) elements contains \( 2^n \) subsets. Since \( n(A) = 2 \): \[ n(P(A)) = 2^{n(A)} = 2^2 = 4 \] 4. **List the Elements of the Power Set \( P(A) \)**: The power set \( P(A) \) will include: - The empty set \( \phi \) - The set containing the first element \( \{ \phi \} \) - The set containing the second element \( \{ \{ \phi \} \} \) - The set containing both elements \( \{ \phi, \{ \phi \} \} \) Therefore, we can write: \[ P(A) = \{ \phi, \{ \phi \}, \{ \{ \phi \} \}, \{ \phi, \{ \phi \} \} \} \] 5. **Conclusion**: The power set \( P(A) \) has 4 elements, which are: \[ P(A) = \{ \phi, \{ \phi \}, \{ \{ \phi \} \}, \{ \phi, \{ \phi \} \} \} \] ### Final Answer: The power set \( P(A) \) is: \[ P(A) = \{ \phi, \{ \phi \}, \{ \{ \phi \} \}, \{ \phi, \{ \phi \} \} \} \]
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