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If volume of a sphere is changing at a r...

If volume of a sphere is changing at a rate of `20 cm^(3)//sec`, then at what rate radius will be changing at the instant when radius is 5 cm ?

Text Solution

Verified by Experts

Volume of sphere is given by
`V=(4)/(3)pir^(3)`
Differentiate with respect to time
`(dV)/(dt)=(4)/(3)pi xx 3r^(2)""(dr)/(dt)`
`implies (dV)/(dt)=4pir^(3)""(dr)/(dt)`
`implies (dr)/(dt)=((dV)/(dt))/(4pir^(2))=(20)/(4pixx25)=(1)/(5pi)` cm/ second .
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