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The slope of normal to the curve x^(3)=...

The slope of normal to the curve ` x^(3)=8a^(2)y, a gt 0` at a point in the first quadrant is `-(2)/(3)` , then point is

A

(2a,-a)

B

(2a,a)

C

(a,2a)

D

(a,a)

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The correct Answer is:
B
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