Find the length of the foot of perpendicular drawn from the point P(a, b, c) on x-axis, y-axis and
z-axis respectively.

Explanation

PA, PB and PC are the perpendicular distances of point P from OX, OY and OZ reapectively
In right triangle APL, we get
`AP^(2) = AL^(2) + PL^(2)`
`rArr AP^(2) = y^(2) +z^(2)`
` [therefore AL= OB = b and PL = OC =c]`
`rArr AP = sqrt(y^(2)+z^(2))`
Now, in right triangle PLB,
`PB^(2) = BL^(2) +PL^(2)`
`rArr PB^(2) = a^(2) +c^(2)`
`[therefore BL = OA = a and PL = OC = c]`
`rArr PB = sqrt(a^(2)+c^(2))`

Similarly, in right triangle PCN
`PC^(2) = CN^(2) + NP^(2)`
`rArr PC^(2) = a^(2) + b^(2) [ therefore CN = OA = a and NP =OB=b]`
`rArr PC = sqrt(a^(2)+ b^(2))`