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Find the angle between the line vecr = (...

Find the angle between the line `vecr = (hati+ hatj + hatk) + lambda (2hatl - hatj + hatk), ` and the plane `vecr cdot (3hatl + hatj + hatk) =6`.

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Verified by Experts

Angle between a line and a plane is given by
`sin theta = (vecb cdot vecn)/(abs(vecb)abs(vecn))`
Here `vecb=2hati-hatj+hatk`
`vecn=3hati-hatj+hatk`
So `sin theta = (6-1+1)/(sqrt(6)xx sqrt(11))=6/(sqrt(6)xxsqrt(11))`
`theta = sin ^(-1)(sqrt(6/11))`
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