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The direction cosines of the normal to t...

The direction cosines of the normal to the plane
`x + 2y - 3z + 4 = 0` are

A

`(-1)/sqrt(14), (-2)/sqrt(14),3/sqrt(14)`

B

`(1)/sqrt(14), (2)/sqrt(14),3/sqrt(14)`

C

`(-1)/sqrt(14), (2)/sqrt(14),3/sqrt(14)`

D

`(1)/sqrt(14), (-2)/sqrt(14),(-3)/sqrt(14)`

Text Solution

Verified by Experts

The correct Answer is:
A
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AAKASH INSTITUTE-THREE DIMENSIONAL GEOMETRY -ASSIGNMENT SECTION - A
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