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Find the vector equation to the plane th...

Find the vector equation to the plane through the point `(2,1,-1) ` passing through the line of intersection of the planes `vecr.(hati+3hatj-hatk)=0 ad vecr.(hatj+2hatk)=0`

A

`vecr cdot (hati + 9hatj + 11hatk)= 0`

B

`vecr cdot (hati + 9hatj + 11hatk)= 6`

C

`vecr cdot (hati - 3hatj - 13hatk)= 0`

D

`vecr cdot (2hati - 3hatj - 4hatk)= 0`

Text Solution

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The correct Answer is:
A
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Find the vector equation to the plane through the point (2,1,-1) passing through the line of intersection of the planes vecr.(hati+3hatj-hatk)=0 and vecr.(hatj+2hatk)=0

Find the vector equation of the plane passing through the point (1,1,1) and passing through the intersection of the planes vecr.(hati-hatj+3hatk)+1=0 and vecr.(2hati+hatj-hatk)-5=0 .

The line of intersection of the planes vecr . (3 hati - hatj + hatk) =1 and vecr. (hati+ 4 hatj -2 hatk)=2 is:

Find the equation of the plane through the point hati+4hatj-2hatk and perpendicular to the line of intersection of the planes vecr.(hati+hatj+hatk)=10 and vecr.(2hati-hatj+3hatk)=18.

The vector equation of the line of intersection of the planes vecr.(2hati+3hatk)=0 and vecr.(3hati+2hatj+hatk)=0 is

The vector parallel to the line of intersection of the planes vecr.(3hati-hatj+hatk) = 1 and vecr.(hati+4hatj-2hatk)=2 is :

Prove that the equaton of a plane through point (2,-4,5) and the line o lintersection of the planes vecr.(2hati+3hatj-hatk) = 1 and vecr.(3hati+hatj-2hatk) = 2 is vecr.(2hati+8hatj+7hatk) = 7 .

Find the equation of the plane passing through the line of intersection of the planes vecr.(hati+hatj+hatk)=1 and vecr.(2hati+3hatj-hatk)+4=0 and parallel to x-axis.

Find the angles between the planes vecr(hati-2hatj-2hatk)=1 and vecr(3hati-6hatj+2hatk)=0

AAKASH INSTITUTE-THREE DIMENSIONAL GEOMETRY -ASSIGNMENT SECTION - B
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