Home
Class 12
MATHS
A plane passes through (1,-2,1) and is ...

A plane passes through (1,-2,1) and is perpendicualr to two planes` 2x-2y+z=0" and "x-y+2z=4,` then the distance of the plane from the point (1,2,2) is

Text Solution

Verified by Experts

The correct Answer is:
5202
Promotional Banner

Topper's Solved these Questions

  • THREE DIMENSIONAL GEOMETRY

    AAKASH INSTITUTE|Exercise ASSIGNMENT SECTION - J|10 Videos

  • THREE DIMENSIONAL GEOMETRY

    AAKASH INSTITUTE|Exercise ASSIGNMENT SECTION - H|4 Videos

  • STRAIGHT LINES

    AAKASH INSTITUTE|Exercise SECTION-J (AAKASH CHALLENGERS QUESTIONS)|5 Videos

  • TRIGNOMETRIC FUNCTIONS

    AAKASH INSTITUTE|Exercise Section - J (Akash Challengers Question)|15 Videos

Similar Questions

Explore conceptually related problems

A plane passes through (1, -2, 1) and is perpendicular to two planes 2x-2y+z=0 and x-y+2z=4. The distance of the plane from the point (0, 2, 2) is

Equation of plane passing through (-1,-1,2) and perpendicular to two planes x-2y+z=4 and x+2y-2z+4=0 is

find distance of the plane 2x-y+3z=4 from point (1,0,-2)

A plane passes through the point (1,-2,3) and is parallel to the plane 2x-2y+z=0 . The distance of the point (-1,2,0) from the plane, is

A plane P = 0 passing through the point (1, 1, 1) is perpendicular to the planes 2x-y+2z=5 and 3x+6y-2z=7 . If the distance of the point (1, 2, 3) from the plane P = 0 is k units, then the value of 34k^(2) is equal to