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If vecOA=veca,vecOB=vecb,vecOC=2veca+3ve...

If `vecOA=veca,vecOB=vecb,vecOC=2veca+3vecb,vecOD=veca-2vecb`, the length of `vecOA` is three times the length of `vecOB` and `vecOA` is perpendicular to `vecDB`, then `(vecBDxxvecAC).(vecODxxvecOC)` is

A

`7vecaxxvecb|^(2)`

B

`42|vecaxxvecb|^(2)`

C

0

D

1

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AAKASH INSTITUTE-VECTOR ALGEBRA-ASSIGNMENT (SECTION-A)
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