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If veca+2vecb=3vecb=0, then vecaxxvecb+v...

If `veca+2vecb=3vecb=0, then vecaxxvecb+vecbxxvecc+veccxxveca=` (A) `2(vecaxxvecb)` (B) `6(vecbxxvecc)` (C) 3(vecxxveca)` (D) 0

A

`6(vecbxxvecc)`

B

`2(vecaxxvecb)`

C

`3(veccxxveca)`

D

0

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The correct Answer is:
1,2,3
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