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The interior angle bisector of angle A f...

The interior angle bisector of angle A for the triangle ABC whose coordinates of the vertices are `A(-8,5), B(-15,-19) and C(1,-7)` has the equation `ax+2y+c=0` Find 'a' and 'c'

Text Solution

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We are given co-ordinates `A(-8,5),B(-15,-19) and C(1,-7)`.
Equation of line AB,
`y-5= (-19-5)/(-15+8)(x+8)`
`=>7(y-5)=24(x+8)`
`=>7y-35=24x+192`
`=>24x-7y+227=0`
Equation of line AC,
`y-5=(-7-5)/(1+8)(x+8)`
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