Water filled in an empty tank of area 10 A through a tap of cross sectional area A. The speed of water flowing out of tap is given by v(m/s)`=10(1-sin((pi)/(30)t)` where `t` is in second. The height of water level from the bottom of the tank at `t=15` second will be:

A cylindrical container of cross-section area, A is filled up with water upto height 'h' Water may exit through a tap of cross sectional area 'a' in the bottom of container. Find out (a) Velocity of water just after opening of tap. (b) The area of cross-section of water stream coming out of tape at depth h_(0) below tap in terms of 'a' just after opening of tap. (c) Time in which conainer becomes empty. (Given : ((a)/(A))^(1//2) = 0.22, h = 20 cm , h_(0) = 20 cm

A cylindrical container of cross-section area, A is filled up with water upto height 'h' Water may exit through a tap of cross sectional area 'a' in the bottom of container. Find out (a) Velocity of water just after opening of tap. (b) The area of cross-section of water stream coming out of tape at depth h_(0) below tap in terms of 'a' just after opening of tap. (c) Time in which conainer becomes empty. (Given : ((a)/(A))^(1//2) = 0.22, h = 20 cm , h_(0) = 20 cm

Water is flowign through a cylindrical pipe of cross section area 0.09 pi m^(2) at a speed of 1.0 m/s. If the diameter of the pipe is halved, then find the speed of flow of water through it

The level of water in a tank is 5 m high . A hole of the area 10 cm^2 is made in the bottom of the tank . The rate of leakage of water from the hole is

The level of water in a tank is 5 m high . A hole of the area 10 cm^2 is made in the bottom of the tank . The rate of leakage of water from the hole is

A hemi-spherical tank of radius 2 m is initially full of water and has an outlet of 12c m^2 cross-sectional area at the bottom. The outlet is opened at some instant. The flow through the outlet is according to the law v(t)=0.6sqrt(2gh(t)), where v(t) and h(t) are, respectively, the velocity of the flow through the outlet and the height of water level above the outlet and the height of water level above the outlet at time t , and g is the acceleration due to gravity. Find the time it takes to empty the tank.

A hemi-spherical tank of radius 2 m is initially full of water and has an outlet of 12c m^2 cross-sectional area at the bottom. The outlet is opened at some instant. The flow through the outlet is according to the law v(t)=0.6sqrt(2gh(t)), where v(t) and h(t) are, respectively, the velocity of the flow through the outlet and the height of water level above the outlet and the height of water level above the outlet at time t , and g is the acceleration due to gravity. Find the time it takes to empty the tank.

A hemi-spherical tank of radius 2 m is initially full of water and has an outlet of 12c m^2 cross-sectional area at the bottom. The outlet is opened at some instant. The flow through the outlet is according to the law v(t)=sqrt(0. 62gh(t)), where v(t) and h(t) are, respectively, the velocity of the flow through the outlet and the height of water level above the outlet and the height of water level above the outlet at time t , and g is the acceleration due to gravity. Find the time it takes to empty the tank.

A hemi-spherical tank of radius 2 m is initially full of water and has an outlet of 12c m^2 cross-sectional area at the bottom. The outlet is opened at some instant. The flow through the outlet is according to the law v(t)=0.6sqrt(2gh(t)), where v(t) and h(t) are, respectively, the velocity of the flow through the outlet and the height of water level above the outlet and the height of water level above the outlet at time t , and g is the acceleration due to gravity. Find the time it takes to empty the tank.

In the previous question, at the mouth of the tap the area of cross-section is 2.5 cm^2 and the speed of water in 3 m//s . The area of cross-section of the water column 80 cm below the tap is.