Point charge `q_(1) = 2 mu C` and `q_(2) = - 1mu C` are kept at points `x = 0` and `x = 6` respectively. Electrical potential will be zero at points

Point charges q_(1) =4 mu C and q_(2) = -2 mu C are kept at point x = 0 and x = 4 respectively , electrical potential will be zero at points (where x is in cm)

Point charges + 4q, -q and +4 q are kept on the X-axis at points x = 0, x = a and x = 2 a respectively

Two point charges q_(1)(sqrt(10)mu C) and q_(2)(-25mu C) are placed on the x-axis at x = 1 m and x = 4 m respectively. The electric field (in V/m) at a point y =3 m on y-axis is, ["take "(1)/(4piin_(0))=9xx10^(9)Nm^(2)C^(-2)]

Two point charges q_(1)(sqrt(10)mu C) and q_(2)(-25mu C) are placed on the x-axis at x = 1 m and x = 4 m respectively. The electric field (in V/m) at a point y =3 m on y-axis is, ["take "(1)/(4piin_(0))=9xx10^(9)Nm^(2)C^(-2)]

Two point charges of magnitude 4 mu C and-4 mu C are kept at points (-2 cm, 0) and (2 cm, 0) respectively. Calculate the magnitude of electric field intensity at points (0, 2 cm).

Two point charges of, 1 mu C and -1 mu C are kept at (-2 m, 0) and (2 m, 0) respectively. Calculate the electric field at point (0, 5 m).

Two point charges q_(1) = 4 mu C and q_(2) = 9 mu C are placed 20 cm apart. The electric field due to them will be zero on the line joining them at distamce of

Two point charges q_(1) = 2 mu C and q_(2) = 1 mu C are placed at distances b = 1 cm and a = 2 cm from the origin on the Y and X axes as shown. The electric field vector at point P(a, b) will subtend an angle theta with X axis is given by

Point charges +4q, -q and +4q are kept on the x-axis at points x=0,x=a and x=2a respectively, then