The length of a magnet of moment `5Am^(2)` is `14cm`. The magnetic induction at a point, equidistant form both the poles is `3.2xx10^(-5)Wb//m^(3)`. The distance of the point form either pole is

The pole strength of a bar magnet of magnetic moment 5 Am^(2) and geometric length 6 cm is

Force acting on a magnetic pole of 7xx 10^(-2) Am is 31.5 N. Magnetic field at that point is …

A short magnet of moment 6.75 Am^(2) produces a neutal point on its axis. If horizontal component of earth's magnetic field is 5xx10^(-5) "Wb"//m^(2) , then the distance of the neutal point should be

A short magnet of moment 6.75 Am^(2) produces a neutal point on its axis. If horizontal component of earth's magnetic field is 5xx10^(-5) "Wb"//m^(2) , then the distance of the neutal point should be

If the moment of a magnet is 0.4 A-m^(2) and force acting on each pole in a uniform magnetic field of induction 3.2 xx10^(-5) Wb//m^(2) is 5.12 xx 10^(-5) N , then find the distance between the poles of the magnet.

The pole strength of a horse shoe magnet is 90Am and distance between the poles is 6 cm . The magnetic induction at mid point of the line joining the poles is,

The magnetic moment of a bar magnet of geometric length 20 cm is 3.6xx10^(-6) Am^(2) The magnetic length is 90% of its geometric length the pole strength is