" fa quadrant of a circle have the coordinates "(1,3)" and "(3,1)," Then the centre of such a circle "

The ends of a quadrant of a circle have the coordinates (1,3) and (3,1). Then the center of such a circle is

The ends of a quadrant of a circle have the coordinates (1, 3) and (3, 1). Then the center of such a circle is

The ends of a quadrant of a circle have the coordinates (1, 3) and (3, 1). Then the center of such a circle is

The ends of a quadrant of a circle have the coordinates (1, 3) and (3, 1). Then the center of such a circle is

The extermities of a diameter of a circle have coordinate (-4,-3) and (12,-1). The length of the segment cut off by the circle on y -axis is

A diameter of a circle has the extreme points (7,9) and (-1,-3) . The coordinates of the centre of the circle are -

The coordinates of one end point of a diameter of a circle are (4,-1) and the coordinates of the centre of the circle are (1,-3) . Find the coordinates of the other end of the diameter.

Show that the points (2, 0), (5, -3), (2, -6) and (-1, -3) are concyclic, find the equation of the circle on which the points lie and the coordinates of the centre of the circle.

If the coordinate of one end of a diameter of a circle is (3,4) and the coordinates of its centre is (-3,2) then the coordinate of the other end of the diameter is .

The coordinates of ond point of a diameter of a corcle are (4,-1) and the cordinates of the centre of the circle are (1,-3). Find the coordinates of the other end of the diameter.