In YDSE of equal width slits, if intensity at the center of screen is `I_(0)`, then intensity at a distance of `beta // 4` from the central maxima is

In YDSE, having slits of equal width, let beta be the fringe width and I_(0) be the maximum intensity. At a distance x from the central brigth fringe, the intensity will be

In YDSE, having slits of equal width, let beta be the fringe width and I_(0) be the maximum intensity. At a distance x from the central brigth fringe, the intensity will be

In a double slit experiment, the separation between the slits is d = 0.25 cm and the distance of the screen D = 100 cm from the slits. If the wavelength of light used is lambda = 6000 Å and I_(0) is the intensity of the central bright fringe, the intensity at a distance x =4xx10^(-5)m from the central maximum is

In Young's double-slit experiment d//D = 10^(-4) (d = distance between slits, D = distance of screen from the slits) At point P on the screen, resulting intensity is equal to the intensity due to the individual slit I_(0) . Then, the distance of point P from the central maximum is (lambda = 6000 Å)

In Young's double-slit experiment d//D = 10^(-4) (d = distance between slits, D = distance of screen from the slits) At point P on the screen, resulting intensity is equal to the intensity due to the individual slit I_(0) . Then, the distance of point P from the central maximum is (lambda = 6000 Å)

In a double slit experiment the separation between the slits is d and distance of screen from slits is D. If the wavelenth of light used is lamda and I is the intensity of central bright fringe, then intensity at distance x from central maximum is given by