lf in a triangle `ABC, a=6,b=3 and cos (A-B)=4/5`. find the area of the triangle.

If in a triangle ABC,a=6,b=3 and cos(A-B)=(4)/(5) find the area of the triangle.

(i) If a:b:c= 2:3:4 and s=27 inches, find the area of the triangle ABC. (ii) If in a triangle ABC, a=6, b=3 and cos(A-B) =4/5 then find its area.

ABC is a triangle where a=6, b=3 and cos(A-B)=4/5 (i) Area of the triangle ABC (in sq. units) is-

In Delta ABC , a= 6 ,b=3 and cos (A-B) = 4/5 .Then are of triangle is

If in a triangle ABC , a = 6 , b = 3 and cos (A -B) = 4/5 ,then its area in square units, is

In a triangle ABC, two sides are a = 6, b = 3 and cos(A-B) =(4)/(5) then the area of the triangle is

ABC is a triangle where a=6, b=3 and cos(A-B)=4/5 Value of angle C is-

In Delta ABC, if a = 6, b=3 and cos (A-B) = (4)/(5) " then " angle C =

In triangle ABC , if a=3, b=4, and c=5, then find the value of cosA.