In the figure, `angleBED=angleBDE` and E is the middle point of BC. Prove that `(AF)/(CF)=(AD)/(BE)`

In the figure,/_BED=/_BDE and E is the middle point of BC. Prove that (AF)/(CF)=(AD)/(BE)

In the figure angleA=angleB and AD=BE then……….

In the figure, if angleA=angleB and AD=BE. Prove that CD = CE.

In Figure,AD, and BE are medians of ABC and BE||DF. Prove that CF=(1)/(4)AC .

In Figure,AD=AE and D and E are points on BC such that BD=EC .Prove that AB=AC

A,B,C and D,E,f are two of collinear points. Prove that AD||CF

In the fig. AD is a median of triangle ABC and E is the mid point of AD, also BE meets AC in F. prove that AF=1/3AC

Given : AB // DE and BC // EF. Prove that: (AD)/(DG) = (CF)/(FG)

In the given figure, triangle ABC is a right triangle with angleB=90^(@) and D is mid-point of side BC. Prove that : AC^(2)=AD^(2)+3CD^(2)

AD BE and CF are the medians of a Delta ABC .Prove that 2(AD+BE+CF)<3(AB+BC+CA)<4(AD+BE+CF)