A tank is filled up to a height `2H` with a liquid and is placed on a platform of height `H` from the ground, the distance x from the ground where a small hole is punched to get the maximum range R is
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A tank is filled upto a height h with a liquid and is placed on a platform of height h from the ground. To get maximum range x_(m) a small hole is punched at a distance of y from the free surface of the liquid. Then

A tank is filled upto a height h with a liquid and is placed on a platform of height h from the ground. To get maximum range x_(m) a small hole is punched at a distance of y from the free surface of the liquid. Then

A tank is filled upto a height h with a liquid and is placed on platform of height h from the ground. To get maximum range x_(m) a small hole is punched at a distance of y from the free surface of the liquid. Then

A tank is filled to a height H. The range of water coming out of a hole which is a depth H//4 from the surface of water level is

A tank is filled to a height H. The range of water coming out of a hole which is a depth H//4 from the surface of water level is

A tank is filled with water to a height H. A hole is punched in the wall at a depth h below the water surface. Find the distance x from the wall at which the stream strikes the floor. Could a hole be punched at another depth so that this second stream would have the same range? If so at what depth? For what value of h is range maximum?

The gravitational potential energy at the height of h from the ground is

A cylinderical vessel is filled with water up to height H. A hole is bored in the wall at a depth h from the free surface of water. For maximum range h is equal to