[2x-y+3z=9],[x+y+2=6],[x-y+z=],[-2x+y=7]

Statement - I The soluton of the system of equations 2x-y+3z=9,x+y+z=6,x-y+z=2 is x=1,y=2,z=3 Statement - II : The solution of the system of equations x+2y-z=3,3x=y+2z=1 , 2x-2y+3z=2 is x=-1,y=4,z=4 Which of the above Statement(s) is true ?

Solve 2x-y+3z=9,x+y+z=6 and x-y+z=2 by matrix method.

2x-y+z=6,x+2y+3z=3,3x+y-z=4

x+y+z=4 2x-y+z=-1 2x+y-3z=-9

By using Cramer's rule solve 2x-y+3z=9,x+y+z=6,x+y+z=2 .

Solve the following equations using Cramer's Rule: 2x-y+3z=9,x+y+z=6,x-y+z=2

Find the value of x,y,z using Cramer's Rule 2x-y+3z=9,x+y+z=6,x-y+z=2

Prove that Det [[x + y + 2z, x, y], [z, y + z + 2x, y], [z, x, z + x + 2y]] = 2 (x + y + z) ^ 3

Find the values of x, y,z from the following equations i) [[4, 3 ], [x, 5]]=[[y , z], [1 , 5]] ii) [[x+y , 2] , [5+z, x y]]=[[6 , 2] , [5, 8]] iii) [[x+y+z], [x+z] , [y+z]]=[[9] , [5 ] ,[7]]

Solve using matrices, for x,y and z: 2x-y-z = 7, 3x+y - z = 7, x + y - z = 3.