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36x^(2)+4y^(2)=144...

36x^(2)+4y^(2)=144

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Find the coordinates of the foci, the vertices, the length of major axis, the minor axis, the eccentricity and the length of the latus rectum of the ellipse. 36 x^2+4y^2=144

A variable chord of the circle x^(2)+y^(2)=4 is drawn from the point P(3,5) meting the circle at the point A and B. A point Q is taken on the chord such that 2PQ=PA+PB The locus of Q is x^(2)+y^(2)+3x+4y=0x^(2)+y^(2)=36x^(2)+y^(2)=16x^(2)+y^(2)-3x-5y=0

What is the eccentricity of the conic 4x^(2)+9y^(2)=144 ?

The foci of the ellipse 36x^(2) + 9y^(2) = 324 are

The eccentricity of the conic 36x^(2)+144y^(2)-36x-96y-119=0 is

The eccentricity of the conic 36 x^(2)+144 y^(2)-36 x-96 y-119=0 is

If x=-2 and y=1, by using an identity find the value: (4y^(2)-9x^(2))(16y^(4)+36x^(2)y^(2)+81x^(4))