An earth's satellite makes a circle around the earth in 90 minutes. Calculate the height of the satellite above the earth's surface. Given radius of the earth is 6400 km and g=980 `cms^(-2)`

An Earth's satellite makes a circule around the Earth in 100 minutes. Calculate the height of the satellite above the Earth's surface. Given the radius of the Earth is 6400 km g = 10 ms^(-2) . Use pi^(2) = 10 .

A satellite contructs a circle around the earth in 90 minutes. Determine the height of the satellite above the earth's surface.

A satellite contructs a circle around the earth in 90 minutes. Determine the height of the satellite above the earth's surface.

An artificial satellite completes a circle around earth in 120 minutes. Calculate the height of the satellite above the earth's surface. Take, radius of earth = 6,400 km g = 9.8 m//s^(2)

An earth satellite makes a complete revolution around the earth in 120 minutes. If the orbit is circular calculate the height of satellite above the earth. Radius of the earth = 6400 km g = 9.8 ms^(-2) .

Find the velocity of a satellite at height 80 km from earth. If the radius of earth is 6400 km

Find the velocity of a satellite at height 80 km from earth. If the radius of earth is 6400 km

Calculate the height of the Apple (India's first geostationary satellite) above the surface of the earth (Radius of the earth = 6400 km and g = 9.8 ms^(-2) )

A satellite of mass 1000 kg moves in a circular orbit of radius 7000 km around the earth. Calculate the total energy required to place the satellite in orbit from earth's surface. Take Radius of earth =6400 km and g=10 m*s^(-2) .

An artificial satellite makes two revolutions per day around the earth. If the acceleration due to gravity on the surface of the earth is 9.8 m//s^2 and the radius of the earth is 6400 km, calculate the distance of satellite from the surface of the earth