`f(x)=x^2,f i n d(f(1. 1)-f(1))/(1. 1-1)`

if f(x)=x^(n) then f(1)+f'(1)/(1!)+f''(1)/(2!)+...+(f^(n)(1))/(n!) is equal to

Given f(x)=4x^(8), then f'((1)/(2))=f'(-(1)/(2))(b)f((1)/(2))=-f'(-(1)/(2))(c)f(-(1)/(2))=f(-(1)/(2))(d)f((1)/(2))=f'(-(1)/(2))

Given f(x)=4x^8 , then (a) f'(1/2)=f'(-1/2) (b) f(1/2)=-f'(-1/2) (c) f'(-1/2)=-f'(1/2) (d) f(1/2)=f'(-1/2)

if f(x) = x^n then the value of f(1) - (f'(1))/(1!) + (f''(1))/(2!) + ---+((-1)^n f''^--n times (1))/(n!)

if f(x) = x^n then the value of f(1) - (f'(1))/(1!) + (f''(1))/(2!) + ---+((-1)^n f''^--n times (1))/(n!)

If f(x) , x^n , then the value of f(1) = (f'(1))/(1!) + (f''(1))/(2!) - (f'''(1))/(3!) + ….+ (((-1)^n f^n (1))/(n!))

if f(x)=x^(n) then the value of f(1)-(f'(1))/(1!)+(f''(1))/(2!)+--+((-1)^(n)f^(prime--n)xx(1))/(n!)

f(x)=(lim)_(n rarr oo)(x)/(x^(2n)+1) Then ,Af(1^(+))+f(1^(-1))=0Bf(1^(+))+f(1^(-))+f(1)=(3)/(2)cf(-1^(+))+f(-1^(-))=-1Df(1^(+))+f(-1^(-))=0