" lve for "x:((2x)/(x-5))^(2)+((2x)/(x-5))-24=0,x!=5

((2x) / (x-5)) ^ (2) +5 ((2x) / (x-5))-24 = 0

(x-5)(x-6)=(25)/((24)^(2))

Solve for x:5^(2x)-16.5^(x)-225=0

Solve the equation : (5)/(2-x)+(x-5)/(x+2)+(3x+8)/(x^(2)-4)=0

lim_(x to 0) ((2x-3)(3x-4))/((4x-5)(5x -6))

lim_(x to 0) ((2x-3)(3x-4))/((4x-5)(5x -6))

The measure of angles of a hexagon are x^(0),(x-5)^(0),(x-5)^(0),(2x-5)^(0),(2x-5)^(0),(2x+20)^(0) Find the value of x.

If : f(x) {: (=(x^(2)+3x-10)/(x^(2)+2x-15)", ... "x!= -5 ),(=a", ... "x = -5 ):} is continuous at x = 5 , then : a =