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A body falling from a high mimaret travels 40 meters in the last 2 seconds of its fall to ground. Height of minaret in meters is (take g=10(m)/(s^2) )

A body falling from a high mimaret travels 40 meters in the last 2 seconds of its fall to ground. Height of minaret in meters is (take g=10(m)/(s^2) )

A body falling from a height travels 40 m in the last 2s of its fall to ground. The height in meter is

A body dropped from top of a tower falls through 40 m during the last two seconds of its fall. The height of tower in m is ( g= 10 m//s^2)

A body dropped from top of a tower falls through 40 m during the last two seconds of its fall. The height of tower in m is ( g= 10 m//s^@)

If body travels half of its path in the last second of its fall from rest, find the time and height of its fall.

If body travels half of its path in the last second of its fall from rest, find the time and height of its fall.

If body travels half of its path in the last second of its fall from rest, find the time and height of its fall.

A stone dropped from the top of a tower travels (5)/(9) th of the height of tower during the last second of fall. Height of the tower is: (Take g = 10 m//s^(2) )

A body travels half of its total path in the last second of its fall from rest.Find the height from which it falls and the time of flight.