" 19."(3)/(4x+3)=(1)/(4x)

Solve : frac(3)(4x+3) = frac(1)(4x)

Find and correct the error : 3/(4x+3) =1/(4x)

Solve for x in (4x-1)/(4x+1)+(4x+1)/(4x-1)=(10)/(3)

(3)/(5)x^2-(19)/(5)x+4

Solve : (5x -2)/(3) + (4x+3)/(2) = (3x+19)/(2)

The largest integral value of x which satisfies the inequality (4x+19)/(x+5)<(4x-17)/(x-3), is 2 (b) 3 (c) 4 (d) 1

The largest integral value of x which satisfies the inequality (4x+19)/(x+5)<(4x-17)/(x-3), is 2 (b) 3(c)4 (d) 1

find the largest integrel value of x which satisfies the inqequelity (4x+19)/(x+5)<(4x-17)/(x-3)

If f(x)=64x^(3)+(1)/(x^(3)) and alpha,beta are the roots of 4x+(1)/(x)=3. Then

if x+(1)/(4x)=(3)/(2) find the value of 8x^(3)+(1)/(8x^(3))