[" (a) "x=2,y=1quad " (b) "x=1,y=1],[" 12.afe "10^(2y)=25," th "10^(-y)" artar "(1)/(6)-]

If 10^(2y)=\ 25\ , then 10^(-y) equals (a) -1/5 (b) 1/(50) (c) 1/(625) (d) 1/5

[" The area that is enclosed in the "],[" circle "x^(2)+y^(2)=2" which is not "],[" common area enclosed by "],[y=x&y^(2)=x" is "],[[" (A) "(1)/(12)(2 pi-1)," (b) "],[" (B) "(1)/(6)(12 pi-1),(1)/(12)(6 pi-1)],[" (D) "(1)/(12)(12 pi-1)]]

If 10^(2y)=25, then 10^(-y) equals -(1)/(5)(b)(1)/(50) (c) (1)/(625) (d) (1)/(5)

I. x^(2)/2 + x - 1/2 = 1 II. 3y^(2) - 10y + 8 = y^(2) + 2y - 10

If (2.5)^(x)=(0.025)^(y)=10^(3) , then the value of (1)/(x)-(1)/(y) is

If 2cos alpha = x + (1) / (x), 2cos beta = y + (1) / (y) then (x ^ (10)) / (y ^ (12)) - (y ^ (12)) / ( x ^ (10)) =

I. 10x^(2) - 7x + 1= 0" " II. 35y^(2) - 12y + 1 = 0